\(A>B\)

cách làm

A<B . K CHO MÌNH NHA

\(A=\frac{54\cdot107-53}{53\cdot107+54}=\frac{\left(53+1\right)107-53}{53\cdot107+54}=\frac{53\cdot107+107-53}{53\cdot107+54}=\frac{53\cdot107+54}{53\cdot107+54}=1\)

\(B=\frac{135\cdot268-133}{134\cdot269+135}=\frac{\left(134+1\right)\cdot268-133}{134\cdot269+135}=\frac{134\cdot268+268-133}{34\cdot269+135}=\frac{134\cdot268+135}{134\cdot269+135}=1\)

Vì 1=1 nên A=B

ban tra loi viet de sai roi 269 ma viet thanh 268

A=B

quá dễ

a, A = \(\frac{20^8+1}{20^9+1}\)

Các câu a,b,c,d,e thì bạn sử quy đồng mẫu số hoặc tử số,mình chỉ làm câu h thôi

\(\dfrac{54.107-53}{53.107+54}\)=\(\dfrac{\left(53+1\right).107-53}{53.107+54}\)=\(\dfrac{53.107+107-53}{53.107+54}\)=\(\dfrac{53.107+54}{53.107+54}\)=1

B=\(\dfrac{135.269-133}{134.269+135}\)=\(\dfrac{\left(134+1\right).269-133}{134.269+135}\)=\(\dfrac{134.269+269-133}{134.269+135}\)=

\(\dfrac{134.269+136}{134.269+135}\)>1

=) A<B

a , \(\dfrac{2}{3}\) > \(\dfrac{1}{2}\) > \(\dfrac{1}{3}\)

b , \(\dfrac{4}{41}\) > \(\dfrac{2}{83}\) > \(\dfrac{3}{124}\) > \(\dfrac{5}{207}\)

c , \(\dfrac{24}{13}\) > \(\dfrac{16}{19}\)

d , \(\dfrac{26}{75}\) < \(\dfrac{27}{82}\)

Câu h đã có bạn làm cho nên mk ko làm nữa!

nhanh len nhe ngay mai thi roi

Ta thấy :

A=\(\frac{54.107-53}{53.107+54}=\frac{53.107+107-53}{53.107+54}=\frac{53.107+54}{53.107+54}=1\)

B=\(\frac{135.269-133}{134.269+135}=\frac{134.269+269-133}{134.269+135}=\frac{134.269+136}{134.269+135}>1\)

Vậy A < B

 vi 53/53.107 =1/107 nenA > 54.107+54 < 135.269 < B